- To show that D=C-1B-1A-1 in
2.2#17, we use
a) associativity
b) definition of multiplicative inverse to reduce to I
c) definition of I as the multiplicative identity to remove it
d) all of the above
e) none of the above, because
D is not C-1B-1A-1.
- Assume that Anxn is invertible. Then the columns of A
a) always span Rn and I can explain why
b) always span Rn but I am unsure of why
c) do not necessarily span Rn but I am unsure of why
d) do not necessarily span Rn and I can explain why