1. To show that D=C-1B-1A-1 in 2.2#17, we use
    a) associativity
    b) definition of multiplicative inverse to reduce to I
    c) definition of I as the multiplicative identity to remove it
    d) all of the above
    e) none of the above, because D is not C-1B-1A-1.



  2. Assume that Anxn is invertible. Then the columns of A
    a) always span Rn and I can explain why
    b) always span Rn but I am unsure of why
    c) do not necessarily span Rn but I am unsure of why
    d) do not necessarily span Rn and I can explain why