{VERSION 3 0 "APPLE_68K_MAC" "3.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 } {PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Output" 0 11 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 3 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 0 "" 0 "" {TEXT -1 33 "Katie McDaniel and Calman \+ Lankton" }}{PARA 0 "" 0 "" {TEXT -1 7 "p.96 #5" }}{PARA 0 "" 0 "" {TEXT -1 337 "An object of mass 5kg is given an initial downward veloc ity of 50 m/sec and then allowed to fall under the influence of gravit y. Assume that the force in newtons (N) due to air resistance is -10v where v is the velocity of the object. If the object is initially 50 0 m above the ground, determine when the object will strike the ground ?" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 28 "the mass of the ball is 5 kg" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "m:=5;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"mG\"\"&" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 39 "the force du e to gravity is 9.81 m/sec2" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "g:=9.81;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"gG$\"$\")*!\"#" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 108 "this is the solution to the diffe rential equation: m(dv/dt)=mg-10v, which gives the equation of the vel ocity" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 54 "dsolve(\{diff(v(t) ,t)=((m*g-10*v(t))/m),v(0)=50\},v(t));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/-%\"vG6#%\"tG,&$\"++++0\\!\"*\"\"\"-%$expG6#,$F'!\"#$\"+++]4X! \")" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 52 "we differentiated the velo city to find the position." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 69 "dsolve(\{diff(x(t),t)=4.905000000+45.09500000*exp(-2*t),x(0)=0\},x (t));" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#/-%\"xG6#%\"tG,(-%$expG6#,$F' $!\"#\"\"!$!+++vaA!\")F'$\"+-++0\\!\"*$\"+++vaAF2\"\"\"" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 94 "we set the position equal to 500, which i s the distance to the ground, and solved for time, t." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 61 "solve(-22.54750000*exp(-2.*t)+4.905 000002*t+22.54750000=500);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#$\"+>f*R t*!\")" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 52 "it took 97.3 seconds fo r the ball to hit the ground." }}}}{MARK "0 2 0" 337 }{VIEWOPTS 1 1 0 3 2 1804 }