Arrowhead |
Point |
Compass |
Straight Edge |
Alphabet |
Script View |
Draw circle with center A and radius B. | Postulate 3 |
Draw circle with center B and radius A. | Postulate 3 |
Let C be an intersection of these circles. | Implicit assumption that 2 overlapping circles in the same plane intersect (or need a postulate like If the sum of the radii of two circles is greater than the line joining their centers, then the two circles intersect like on https://mathcs.clarku.edu/~djoyce/java/elements/bookI/propI1.html). |
Connect AC. | Postulate 1 |
Connect BC. | Postulate 1 |
Notice that AC=AB. | Definition 15 and the fact that AC and AB are radii of the circle with center A. |
Notice that BC=BA. | Definition 15 and the fact that BC and BA are radii of the circle with center B. |
Hence AC=AB=BC. | Common Notion 1 and the fact that AC=AB and BC=AB. |
Therefore, ABC is equilateral. | Definition 20. |